Question

calculate the ratio of effusion rates for nitrogen (N2) and neon(ne)
please answer me fast......
i need now

Answer 1

Answer:- The ratio of rate of effusion of nitrogen to neon gas is 0.85.

Solution:- According to Graham's law of effusion rates of gases, "Rate of effusion of a gas is inversely proportional to the square root of it's molar mass."

When we compare the effusion rates of two gases then we use the formula:

$\frac{r_1}{r_2}=\sqrt{\frac{M_2}{M_1}}$

Where r stands for rate of effusion and M stands for molar mass. subscripts 1 and 2 are used for the two gases.

We are asked to compare the rate of effusion of nitrogen gas with neon gas. So, the formula could be written as:

$\frac{r_N_2}{r_N_e}=\sqrt{\frac{M_N_e}{M_N_2}}$

Molar mass of nitrogen is 28.01 gram per mol and molar mass of Ne is 20.18 gram per mol. Let's plug in the molar masses of the two gases in the formula:

$\frac{r_N_2}{r_N_e}=\sqrt{\frac{20.18}{28.01}}$

[tex]\frac{r_N_2}{r_N_e}=0.85

So, the ratio of effusion rates of nitrogen to neon is 0.85.