Question

calculate the ratio of final pressure to original pressure of a gas which was originally kept at 127°C and is heated upto and was heated up to 227°C. The expansion in volume is 10 percentage​

Answer 1

Answer:

The Ratio of final pressure to original pressure is 1.1.

Explanation:

From combined gas law

$\frac{PV}{T}$=constant

⇒$\frac{P_{1} V_{1} }{T_{1} }$=$\frac{P_{2} V_{2} }{T_{2} }$

To find $\frac{P_{2} }{P_{1} }$

Rearranging the above equation

$\frac{P_{2} }{P_{1} }$=$\frac{V_{1} T_{2} }{V_{2} T_{1} }$-------->eqn1

Given that, the gas was originally at T₁=127°C (127+273=400K) and was heated upto T₂=227°C (227+273=500K).

The Volume expansion was 10%

⇒V₁ be the initial volume then V₂=1.1V₁ (V₁+$\frac{10}{100}$V₁)

Substituting the values in eqn1

$\frac{P_{2} }{P_{1} }$=$\frac{V_{1} }{1.1V_{1} }$×$\frac{500}{400}$

⇒ $\frac{P_{2} }{P_{1} }$=$\frac{1}{1.1}$×$\frac{5}{4}$

⇒ $\frac{P_{2} }{P_{1} }$=$\frac{50}{44}$

⇒ $\frac{P_{2} }{P_{1} }$=$\frac{25}{22}$ or 1.1

⇒P₂=1.1P₁