Question

Calculate the ratio of kinetic energies of 3 grams of hydrogen and 4 grams of oxygen at a given temperature

Answer 1

K. E= 3/2*n*r*t
Use this formula to find the ratio

Hope it helps you

Answer 2

Answer: The ratio will be 12 : 1.

Explanation:

Hydrogen and oxygen are the diatomic gases and the formula for kinetic energy is given as:

$K.E.=\frac{5}{2}nRT$    ....(1)

where,

R = Gas constant

T = Temperature of the gas

n = Number of moles of gas

To calculate the number of moles, we use the formula:

$n=\frac{\text{Given mass}}{\text{Molar mass}}$

For Hydrogen:

Molar mass = 2g/mol

Given mass = 3g

$n_H=\frac{3}{2}$

For Oxygen:

Molar mass = 32g/mol

Given mass = 4g

$n_H=\frac{4}{32}=\frac{1}{8}$

Taking the ratio of kinetic energy of hydrogen and oxygen by putting it in equation 1, we get:

$\frac{E_H}{E_O}=\left ( \frac{\frac{3}{2}\times \frac{5}{2}RT}{\frac{1}{8}\times \frac{5}{2}RT} \right )\\\\\frac{E_H}{E_O}=\frac{3}{2}\times \frac{8}{1}\\\\E_H:E_O=12:1$

Hence, the ratio will be 12 : 1.