Question

calculate the ratio of kinetic energies of 3g of H2 and 4g of O2 at a given temperature.​

Answer 1

Hey mate here is the answer to your question

In questiion the 4g of oxygen

And 3g of hydrogen is given

Now we take our avrg kinetic energy formula as:

Avrg  K.E= 2/3 kT

As H2 =2 moles

And oxygen= 32 moles

We get as:

3/2 = 1.5

4/32 = 0.125

So ratio gives 1.5:0.125

Answer 2

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Since the temperature is same for the two gases,we can write the ratio of kinetic energies is in the moles of ${H2}$: moles of ${O2}$.

$\frac{3g ofH2}{2g m^-1}$:$\frac{4g ofO2}{32g mol^-1}$=$\frac{3}{2}$:$\frac{1}{8}$=${12:1}$.