Question

Calculate the ratio of mean square speed of molecules of a gas at 30K and 120K​​​

Answer 1

Answer:

1/2.

Explanation:

Given: molecules of a gas 30k and 120k

To find: the ratio mean square speed of molecules of a gas 30k and 120k

​

Solution:

Now we know that:

v(rms) = √3RT/M

Let v1 and v1 be mean square speed of molecules of a gas 30k and 120k .

Then:

                v1 / v2 = √3RT/M  / √3RT/M

Cancelling the common terms, we get:

                v1 / v2 = √T1 / √T2

Now putting the value of T, we get:

                v1 / v2 = √30 / √120

                 v1 / v2 = 1/√4

                v1 / v2 = 1/2