Question

Calculate the ratio of molecules present in 4.4g of co2 and 1.6g of so2

Answer 1

Answer:

Step-by-step explanation:

Answer 2

Answer:

The ratio is 4:1.

Step-by-step explanation:

To find : Calculate the ratio of molecules present in 4.4g of $CO_2$ and 1.6g of $SO_2$ ?

Solution :

Using the mole formula,

$\text{Mole}=\frac{\text{Given weight}}{\text{Molecular weight}}$

4.4g of $CO_2$

The molecular weight is 44.

$\text{Mole}=\frac{4.4}{44}$

$\text{Mole}=0.1$

1 mole contain $6.022\times 10^{23}$ molecules.

0.1 mole contain $6.022\times 10^{23}\times 0.1$ molecules.

0.1 mole contain $6.022\times 10^{22}$ molecules.

1.6g of $SO_2$

The molecular weight is 64.

$\text{Mole}=\frac{1.6}{64}$

$\text{Mole}=0.025$

1 mole contain $6.022\times 10^{23}$ molecules.

0.025 mole contain $6.022\times 10^{23}\times 0.025$ molecules.

0.1 mole contain $1.5055\times 10^{22}$ molecules.

Ratio of molecules of $CO_2$ to $SO_2$ is

$r=\frac{6.022\times 10^{22}}{1.5055\times 10^{22}}$

$r=\frac{4}{1}$

The ratio is 4:1.