Question

Calculate the ratio of molecules present in 6°6 grm of co2 and 3°2grm of so2

Answer 1

Hello!!

molar mass of CO2 = 44g

44g of CO2 =  6.022 X 1023 molecules of CO2 

So, 1g of  CO2 =  (6.022 X 1023 / 44) moles of CO2

therefore, 6.6g of CO2 =  (6.022 X 1023 X 6.6) / 44  moles of CO2

= 9.033 X 1022 moles of CO2

Step 2::

64g of SO2 = 6.022 X 1023 moles of SO2

So, 1g of SO2 = (6.022 X 1023 / 64) mols of SO2

Therefore, 3.2g of SO2 = (6.022 X 1023 X 3.2) / 64 moles of SO2
= 3.011 X 1022 moles of SO2

So, ratio = (9.033 X 1022) / (3.011 X 1022)

= 3

Thus, ratio will be 3 : 1

hope it helps

Answer 2

Calculate the ratio of molecules present in 6°6 grm of co2 and 3°2grm of so2 ...

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07-Nov-2017 · Step 2:: 64g of SO2 = 6.022 X 1023 moles of SO2 So, 1g of SO2 = (6.022 X 1023 / 64) mols of SO2 Therefore, 3.2g of ...