Calculate the ratio of moles of 3.6 g of water and 4.4 g of carbon dioxide.Atomic mass of C=12u, H=1u,O=16u
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Weight of water = 3.6 g.
Molecular weight of water = 2 + 16 = 18g
No of moles of water = 3.6/18 = 0.2
Weight of carbon dioxide = 4.4 g
Molecular weight of carbon dioxide = 12 + 32 = 44 g
No of moles of carbon dioxide = 4.4/44 = 0.1
Hence, mole ratio of 3.6 g of water and 4.4 g of carbon dioxide = 0.2:0.1 = 2:1.
Molecular weight of water = 2 + 16 = 18g
No of moles of water = 3.6/18 = 0.2
Weight of carbon dioxide = 4.4 g
Molecular weight of carbon dioxide = 12 + 32 = 44 g
No of moles of carbon dioxide = 4.4/44 = 0.1
Hence, mole ratio of 3.6 g of water and 4.4 g of carbon dioxide = 0.2:0.1 = 2:1.
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