calculate the ratio of moles of 3.6g of water and 4.4g of carbon dioxide .Atomic mass of C = 12u , H = 1u , O = 16 u
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mole=mass÷molar mass
=3.6÷18
=1/5 mole
2nd,
mole=mass÷molar mass
=4.4÷44
=1/10
so it will be,
1/5:1/10
=0.2:0.1
=3.6÷18
=1/5 mole
2nd,
mole=mass÷molar mass
=4.4÷44
=1/10
so it will be,
1/5:1/10
=0.2:0.1
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