Physics, asked by agrima2907, 8 months ago

Calculate the ratio of momentum , when
(i) velocity of an object is doubled
(ii)mass of an object is halved
(iii) both mass and velocity are increased by three times.​

Answers

Answered by llɱissMaɠiciaŋll
3

Explanation:

Ek = (1/2) m.v^2

Let m → 2m

And v →2v

Then, Ek = (1/2) (2m).(v/2)^2

==> (1/2) (2m).(v^2/4)

==> (1/2) (m).(v^2/2)

==> Ek/2

Therefore, Kinetic Energy is reduced to half, when mass is doubled, and velocity is halved.

Similarly, when you increase mass to 3 times and decrease the velocity by a factor of 3, the KINETIC ENERGY changes to 1/3^rd.

i.e.,

Ek = {(1/2) m.v^2}/3

and so on…

IS that Okay (thanks)

Answered by NikhilAhire
3

Answer:

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Explanation:

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