calculate the ratio of mommentum when mass of obj halved
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Answer:
2:1
Explanation:
let original mass be m
and velocity be v
new mass = m/2
initial momentum = p1 = m1v1 = mv
new momentum = p2 = m2v2 = (m/2)×v
Ratio of momentum = p1/p2 = mv/(mv/2)
= p1/p2 = 2/1 (mv, mv gets cancelled)
therefore p1:p2 = 2:1
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