Question

Calculate the ratio of Na2O , MgO, CaO, CO2, H2O by their masses.


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Answer 1

Answer:

Ans.

Ans.Sodium carbonate + Ethanoic acid → Sodium ethanoate + Carbon dioxide + Water

Ans.Sodium carbonate + Ethanoic acid → Sodium ethanoate + Carbon dioxide + Water5.3 g + 6 g → 8.2 g + 2.2 g + 0.9 g

Ans.Sodium carbonate + Ethanoic acid → Sodium ethanoate + Carbon dioxide + Water5.3 g + 6 g → 8.2 g + 2.2 g + 0.9 g LHS RHS

Ans.Sodium carbonate + Ethanoic acid → Sodium ethanoate + Carbon dioxide + Water5.3 g + 6 g → 8.2 g + 2.2 g + 0.9 g LHS RHS 11.3 g = 11.3 g

Ans.Sodium carbonate + Ethanoic acid → Sodium ethanoate + Carbon dioxide + Water5.3 g + 6 g → 8.2 g + 2.2 g + 0.9 g LHS RHS 11.3 g = 11.3 g (Mass of reactant) (Mass of product)

Ans.Sodium carbonate + Ethanoic acid → Sodium ethanoate + Carbon dioxide + Water5.3 g + 6 g → 8.2 g + 2.2 g + 0.9 g LHS RHS 11.3 g = 11.3 g (Mass of reactant) (Mass of product) This shows, that during a chemical reaction mass of reactact = mass of product.

Ans.Sodium carbonate + Ethanoic acid → Sodium ethanoate + Carbon dioxide + Water5.3 g + 6 g → 8.2 g + 2.2 g + 0.9 g LHS RHS 11.3 g = 11.3 g (Mass of reactant) (Mass of product) This shows, that during a chemical reaction mass of reactact = mass of product.2. Hydrogen and oxygen combine in the ratio of 1 : 8 by mass to form water. What mass of oxygen gas would be required to react completely with 3 g of hydrogen gas?

Ans.Sodium carbonate + Ethanoic acid → Sodium ethanoate + Carbon dioxide + Water5.3 g + 6 g → 8.2 g + 2.2 g + 0.9 g LHS RHS 11.3 g = 11.3 g (Mass of reactant) (Mass of product) This shows, that during a chemical reaction mass of reactact = mass of product.2. Hydrogen and oxygen combine in the ratio of 1 : 8 by mass to form water. What mass of oxygen gas would be required to react completely with 3 g of hydrogen gas?Ans. Ratio of H : O by mass in water is:

Ans.Sodium carbonate + Ethanoic acid → Sodium ethanoate + Carbon dioxide + Water5.3 g + 6 g → 8.2 g + 2.2 g + 0.9 g LHS RHS 11.3 g = 11.3 g (Mass of reactant) (Mass of product) This shows, that during a chemical reaction mass of reactact = mass of product.2. Hydrogen and oxygen combine in the ratio of 1 : 8 by mass to form water. What mass of oxygen gas would be required to react completely with 3 g of hydrogen gas?Ans. Ratio of H : O by mass in water is: Hydrogen : Oxygen → H2O

Ans.Sodium carbonate + Ethanoic acid → Sodium ethanoate + Carbon dioxide + Water5.3 g + 6 g → 8.2 g + 2.2 g + 0.9 g LHS RHS 11.3 g = 11.3 g (Mass of reactant) (Mass of product) This shows, that during a chemical reaction mass of reactact = mass of product.2. Hydrogen and oxygen combine in the ratio of 1 : 8 by mass to form water. What mass of oxygen gas would be required to react completely with 3 g of hydrogen gas?Ans. Ratio of H : O by mass in water is: Hydrogen : Oxygen → H2O 1 : 8 = 3 : x

Ans.Sodium carbonate + Ethanoic acid → Sodium ethanoate + Carbon dioxide + Water5.3 g + 6 g → 8.2 g + 2.2 g + 0.9 g LHS RHS 11.3 g = 11.3 g (Mass of reactant) (Mass of product) This shows, that during a chemical reaction mass of reactact = mass of product.2. Hydrogen and oxygen combine in the ratio of 1 : 8 by mass to form water. What mass of oxygen gas would be required to react completely with 3 g of hydrogen gas?Ans. Ratio of H : O by mass in water is: Hydrogen : Oxygen → H2O 1 : 8 = 3 : x x = 8 × 3

Ans.Sodium carbonate + Ethanoic acid → Sodium ethanoate + Carbon dioxide + Water5.3 g + 6 g → 8.2 g + 2.2 g + 0.9 g LHS RHS 11.3 g = 11.3 g (Mass of reactant) (Mass of product) This shows, that during a chemical reaction mass of reactact = mass of product.2. Hydrogen and oxygen combine in the ratio of 1 : 8 by mass to form water. What mass of oxygen gas would be required to react completely with 3 g of hydrogen gas?Ans. Ratio of H : O by mass in water is: Hydrogen : Oxygen → H2O 1 : 8 = 3 : x x = 8 × 3 ∴ 24 g of oxygen gas would be required to react completely with 3 g of hydrogen gas.