Calculate the Ratio of no. of atom 1g N2 and 1g NH3.....
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plzz anyone solve this question.
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Answer:
28g N2 = 6.022×10^23atom
1g N2= 6.022×10^23/28 -1
and, 17g NH3= 6.022×10^23
1g NH3= 6.022 ×10^23/17 -2
now 1/2 = 17/28
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