Question

Calculate the ratio of number of pure and hybrid orbital used for bonding in an acetylene molecule​

Answer 1

Acetylene has two 'C' atoms and two 'H' atoms.

Carbon undergoes sp hybridisation.

Number of hybrid orbitals = 2 × 2 = 4

Number of pure orbitals =

4 ( From C ) + 2 ( From H ) = 6

Ratio of number of pure and hybrid orbitals = 4:6 = 2:3

Answer 2

Answer:

2:3

Explanation:

GIVEN - bonding in an acetylene molecule

TO FIND- the ratio of number of pure and hybrid orbital

SOLUTION - we know that acetylene has two C atoms and two H atoms

number of hybrid orbitals = 2×2= 4

number of pure orbitals = 4( from C)+ 2( from h)= 6

Ratio of number of pure and hybrid orbitals = 2:3

FINAL ANSWER - 2:3

#SPJ3