Calculate the ratio of the intensities of the two waves, if amplitude of first beam of light is 1.5 times the amplitude of second beam of light.
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Answer:
Hey Mate!!
Explanation:
Let the amplitudes be 5x and x
Now,resultant waves will have maximum amplitude when both are in phase
They add up 5x+x=6x
During destructive interference the waves are out of phase
The resultant amplitude is x−5x=−4x
♦Maximum intensity = (maximum amplitude) ²
=36x²
♦minimum intensity = (minimum amplitude) ²
=16x²
[Answer is in image]
hope it will help you mate!!
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