Question

CALCULATE THE RATIO OF THE SHORTEST WAVELENGTHS OF THE LYMAN AND BALMER SERIES OF THE SPECTRA?

Answer 1

when an hydrogen electron from level 6-level 2 it shows the transition.

where level ( 6) is higher energy level and (2) is lower energy level the wavelength of the radiation of any electron can be calculates by Rydberg equation. According to this equation as:

1/ w = R 1/ 4  -  1/ 36 where both 1/4 and 1/36 are reciprocal of square of lower and higher energy levels 2 and 6 in Balmer series and R" is Rydberg constant.

so value of both 1/4 and 1/36 is equal to 0.22 and value of R" is equal to

243,728 per meter.

by taking this value we can calculates the wavelength of any energy levels from 2  to 6 hope you will understand now