Question

Calculate the ratio of total internal energy of hydrogen and helium at300k

Answer 1

Answer:

Ratio of internal energy of the given two gas is

$\frac{E_{hydrogen}}{E_{helium}} = \frac{5}{3}$

Explanation:

As we know that total internal energy of ideal gas is sum of the kinetic energy and potential energy of the gas

So we have

$E = \frac{f}{2}nRT$

here let say that hydrogen and helium both gases are of same number of moles

so we have

$\frac{E_{hydrogen}}{E_{helium}} = \frac{f_{hydrogen}}{f_{helium}}$

so hydrogen is diatomic gas which has 5 degrees of freedom while helium is monoatomic gas which has 3 degree of freedom

So we will have

$\frac{E_{hydrogen}}{E_{helium}} = \frac{5}{3}$

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Topic : internal energy of ideal gas

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