Question

Calculate the ratio of volume occupied by 1 mole of o2 and 1 mole of o3

Answer 1

We know 1 mole of gase at NTP has 22.4 litres gas.

 

So, in 1 mole Oxygen there will be 22.4 litres of gas and also in 1 mole ozone there will be 22.4 litres of gas.

 

So, ratio is 1:1

Answer 2

The ratio of volume of oxygen gas and ozone gas is 1 : 1

Explanation:

We are given:

Moles of oxygen gas = 1 mole

Moles of ozone gas = 1 mole

At STP:

1 mole of a gas occupies 22.4 L of volume

Volume occupied by oxygen gas = (1 × 22.4) = 22.4 L

Volume occupied by ozone gas = (1 × 22.4) = 22.4 L

Taking the ratio of the volumes:

$\frac{V_{O_2}}{V_{O_3}}=\frac{22.4L}{22.4L}\\\\\frac{V_{O_2}}{V_{O_3}}=\frac{1}{1}$

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