Question

calculate the refractive index of a glass prism having angle of refraction 60 and angle of minimum deviation 40​

Answer 1

Explanation:

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Answer 2

Answer:

Minimum deviation δ=2i−A

where A is prism angle A=60

o

So δ=40

o

we know

δ=2i−A

40=2i−60

i=50

o

For minimum angle the angle of refraction should be half of prism angle.

So r=A/2=30

o

now using the snell's law

n

air

sini=n

glass

sinr

sin50=n

glass

sin30

n

glass

=1.53 ,