Question

calculate the relative molecular mass after 90 ml of a gas a at 17 degree Celsius and thousands 520 mm pressure which weighs 2.73 gram at STP

Answer 1

According to Avogadro's law :

Molecular mass = Mass of one mole of gas at STP2×mass of one hydrogen atom at STP
2. Mass of one hydrogen atom at STP = 1.67 × 10−24g
3. Also according to the same law :

p1V1n1T1 = p2V2n2T2 = constant

4. So,
n = pVRT = 1520 × 290×10−38.314 × 290 = 0.182
4. Mass of 0.182 moles is 2.73g
So,
Mass of 1 mole = 2.730.182= 15g
3. Molecular mass = 152×1.67×10−24g = 111.11g152×1.67×10−24g =

Answer 2

Answer:

:

According to Avogadro's law :

Molecular mass = Mass of one mole of gas at STP2×mass of one hydrogen atom at STP

2. Mass of one hydrogen atom at STP = 1.67 × 10−24g

3. Also according to the same law :

p1V1n1T1 = p2V2n2T2 = constant

4. So,

n = pVRT = 1520 × 290×10−38.314 × 290 = 0.182

4. Mass of 0.182 moles is 2.73g

So,

Mass of 1 mole = 2.730.182= 15g

3. Molecular mass = 152×1.67×10−24g = 111.11g152×1.67×10−24g =