Question

Calculate the relative molecular mass of CH3COONa.

(C=12, H=1, O=16, Na=23).

explain with steps pls​

Answer 1

Answer:

         82u

Explanation:

CH₃COONa

Atomic Mass OF Carbon (C) = 12u

Atomic Mass OF Hydrogen (H) = 1u

Atomic Mass OF Oxygen (O) = 16u

Atomic Mass OF Sodium (Na) = 23u

                                                   No of carbon atoms = 2

                                                  No of hydrogen atoms = 3

                                                    No of oxygen atoms = 2

                                                     No of sodium atoms = 1

molecular mass of CH₃COONa =

(No of carbon atoms × Atomic Mass OF Carbon) + (No of hydrogen atoms × Atomic Mass OF Hydrogen) + (No of oxygen atoms × Atomic Mass OF Oxygen) + (No of sodium atoms × Atomic Mass OF Sodium)

= (2 × 12) + (3 × 1) + (2 × 16) + (1 × 23)

= 24 + 3 + 32 + 23

= 82u

Answer 2

Answer:

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