Calculate the relative molecular mass of Na₂CO₃.10 H₂O. (Atomic mass: Na=23, C=12, O=16, H=1)
Answers
Answered by
0
Answer:
286
Explanation:
Na2CO3.10H2O
= (2 × 23) + (12 + 3 × 16) + (20 × 1 + 10 × 16)
= 46 + 60 + 180
= 286
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Answered by
0
Answer:
Correct option is B
286
Formula unit mass of Na2CO3
= 2×atomic mass of Na+1×atomic mass of C+3×atomic mass of O
=2×22.98+1×12.01+3×16
=105.97u
Formula unit mass of 10H2O=10×atomic mass of H2O
=10×18.02
=180.02u
Formula unit mass of Na2CO3.10H2O=105.97+180.02
=285.99u
Explanation:
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