Calculate the relative molecular mass of the following compounds a. (NH 2 ) 2 CO [Given C= 12, N=14, O=16, H=1] b. CuSO 4 .5H 2 O [Given Cu=63.5, S=32, H=1, O=16] c. C 12 H 22 O 11 [Given C=12, H=1, O=16]
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(1). 14×2+2×2+12×1+16
28+4+12+16
=60 gmol-1
Explanation:
(2). 63.5+32+9×16+10= 249.5gmol-1 .(3)144+22+176
=342 .
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