Question

Calculate the relative population of the first
two rotational levels for HCl at 300 K given
that the value of the rotational constant of
the molecule is 10.59 cm^-1.​

Answer 1

Answer:

2.71

I think sonot sure

Answer 2

Explanation:

Relative population of the first two rotational levels for HCl at 300 K given that the value of the rotational constant of the molecule is 10.59 cm^-1.​

$e^{\frac{Bhc J(J+1)}{KbT} }$

$e^{\frac{(104.398)(6.262*10^{-34})(2.53 * 10^{3} (2) }{1.38 * 10^{-23} (300)} }$

Therfore solving the above equation we get answer of around 2.713.