Question

Calculate the relative populations of carriers of two energy levels at room temperature if radiation between those levels is 550nm

Answer 1

The relative populations of carriers of two energy levels is $8.194\times10^37$

Explanation:

Given radiation between energy levels = 550nm

The relative populations between two energy levels is given by

$N1/N2=e^(^h^c^/^L^k^T^)$,

where,

 N1 is the population at lower energy level

 N2 is the population at higher energy level

 h is Planck's constant = $6.626 \times 10^-^3^4$ Js

 k is Boltzmann constant = $1.38 \times 10^-^2^3 kg m^2 s^-^2 K^-^1$

 T is the absolute temperature (300K)

 L is the wavelength = 550nm

c is the speed of light = $3 \times 10^8 m/s$

By substituting all the above values,

we get N1/N2 =$8.194\times 10^37$

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