Question

Calculate the required heat energy to change 10 gr of ice at 0°C into water vapour at 100°C.​

Answer 1

Answer:

2100 J

Explanation:

Given that,

Mass of ice, $m = 10\ gm$

1000 gm = 1 kg

10 gm = 0.01 kg

So, $m=0.01\ kg$

Specific Heat of Ice, $c = \~\ 2100 J/Kg ^\circ K$

Temperature values:

$T_1 = 0^\circ C=273 K$

$T_2 = 100^\circ C =373 K$

Formula for Heat Energy = $m\times c \times \triangle T$

Where $\triangle T$ is the change in temperature:

$\triangle T = 373 - 273 = 100K$

Heat Energy = $0.01 \times 2100 \times 100 = 2100 J$

So, required heat energy = ~2100 J