Question

calculate the required heat energy to change 10 grams of ice at o degrees Celsius into water vapour at 100 degrees Celsius ​

Answer 1

Answer:

Explanation:

Heat energy (Q) =ms∆T,where,

m=mass=10grams

S=specific heat=2.10(approx.2),for ice.

∆T=change in temperature=(100-0)

(As final temperature=100°C and

Initial temperature of ice is 0°C)=0°C

Q=10×2×100

Q=2000KJ

Hence, required heat energy is 2000KJ.

Answer 2

Explanation:

To convert 10 gram -10 degree Celsius is 0 degree Celsius 10 gram water the required heat is 80×12+800=960 +800=1760 cal..

To convert 12 gram 0 degree celsius to 100 degree Celsius the required heat is 12×537 =6444...cal

the total heat is (1760+6444)=8204 cal..

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