calculate the required heat energy to change 10gram of ice at 0C into water vapour at 100C
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mass=10g(m)
temp diff = 100-0=100(t)
Specific heat capacity of water( c )=4.2 j per kg kelvin
Q(heat energy)=mxcxt
4.2x100x10=4.2x1000=4200J
The heat energy required = 4200 J
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