calculate the resistance between P and Q in the circuit shown in figure ?
Answers
Answer:
Components connected in parallel are connected so the same voltage is applied to each component. In a parallel circuit, the voltage across each of the components is the same, and the total current is the sum of the currents through each component.
To find the total resistance of all components, the reciprocals of the resistances of each component is added and the reciprocal of the sum is taken. Hence, the Total resistance will always be less than the value of the smallest resistance. That is,
R
total
1
=
R
1
1
+
R
2
1
thatis,R=R
total
−1
.
Components connected in series are connected along a single path, so the same current flows through all of the components. In a series circuit, every device must function for the circuit to be complete.
The total resistance in the circuit is given as sum all the resistances in the circuit. That is, R = R1 +R2 +R3...Rn
In this case, the 2 resistances R in the middle are connected in parallel. So the total resistance is given as, 1/R = 1/R + 1/R = R*R/2R = R/2.
The resistances R and R on the sides are connected in series with the combined parallel resistances R/2.
Hence, the net resistance in the circuit is R + R/2 + R = 2R/5.
12/7
Explanation:
we will divide this circuit into two circuit one from pcq
and 2nd directly pq
since pcq are in series
R =2+2
=4
and both the above circuits are in series therefore
1/Rf = 1/4+1/3
Rf= 12/7