Question

Calculate the resistance of 0.01 N solution of an
electrolyte whose equivalent conductivity is 420
ohm-'cm equiv(The cell constant of the cell is
0.88 cm-!)​

Answer 1

Given :

Normality = 0.01 N

Equivalent conductivity = 420 ohm-cm

Cell constant = 0.88 cm⁻¹

To find =

Resistance of the cell = ?

Solution :

• Equivalent conductivity = k×1000 / N
• k = l/ R×a

• Aeq = l×1000 / R×a

• 420 = 1000×0.88 / R

• R = 1000×0.88 / 420

• R = 2 ohm

The resistance of the cell is 2 ohm