Physics, asked by Avniv5, 10 months ago

calculate the resistance of 1 km long copper wire of radius 1 mm. Resistivity of copper is =
1.72 \times  {10}^{ - 8} \: ohm

Answers

Answered by Anonymous
244

\huge\underline{\underline{\bf \orange{Question-}}}

calculate the resistance of 1 km long copper wire of radius 1 mm. Resistivity of copper is {\sf 1.72×10^{-8}Ω.m}

\huge\underline{\underline{\bf \orange{Solution-}}}

\large\underline{\underline{\sf Given:}}

  • Lenght of wire (L) = 1km = 1000m
  • Radius (r) = 1mm = {\sf 10^{-3}m}
  • Resistivity {\sf (\rho)=1.72×10^{-8}ohm.m}

\large\underline{\underline{\sf To\:Find:}}

  • Resistance (R)

\large{\rm We \: know \: that- }

\large{\boxed{\bf \blue{R=\rho\dfrac{L}{A}} }}

\implies{\sf R = 1.72×10^{-8}×\dfrac{1000}{πr^2} }

\implies{\sf R= 1.72×10^{-8}×\dfrac{1000}{3.14×(10^{-3})^2}}

\implies{\sf R = 1.72×10^{-8}×\dfrac{1000}{3.14×10^{-6}}}

\implies{\sf R = 1.72×10^{-8}×\dfrac{318.4}{10^{-6}} }

\implies{\sf R = 1.72×10^{-8}×318.4×10^6 }

\implies{\sf R = 547.6×10^{-2}}

\implies{\bf \red{ Resistance (R) = 5.4Ω }}

\huge\underline{\underline{\bf \orange{Answer-}}}

Resistance of copper wire is {\bf \red{5.4Ω}}.

Answered by Anonymous
3

Answer:

\large\boxed{\sf{5.5 \;\;\Omega}}

Explanation:

Given a copper wire :

Length, l = 1 km = {10}^{3}\;m

Radius, r = 1 mm = {10}^{-3}\;m

Resistivity, \rho = 1.72 \times {10}^{-8}\; \Omega\:m

To find the resistance, r :

find the Cross sectional area,

 =  > a = \pi {r}^{2}  \\  \\  =  > a = \pi {( {10}^{ - 3} )}^{2}  \\  \\  =  > \sf{ a =  {10}^{ - 6} \pi  \:  \:  \:  {m}^{2} }

Now we know that,

r =  \rho \frac{l}{a}  \\  \\  =  > r =  \frac{1.72 \times  {10}^{ - 8}  \times  {10}^{3} }{ {10}^{ - 6} \pi}  \\  \\  =  > r =  \frac{1.72}{3.14}   \times   {10}^{( - 8 + 3 + 6)}  \\  \\  =  > r = 0.55 \times  {10}^{ 1}  \\  \\  =  > r = 5.5

Hence resistance is \bold{5.5 \;\;\Omega}

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