Question

Calculate the resistance of 2.5 km long aluminium wire of radius 0.5mm. Resistivity of aluminium = 2.7 x 10^-8ohmm

Answer 1

Answer:

Explanation:

LENGTH=2.5*1000=2500M

RADIUS=0.5*10^-3M

RESISTIVITY=2.7*10^-8

RESISTANCE=RESISTIVITY*LENGTH/AREA

RESISTANCE=2.7*10^-8*2500/3.14*0.5*0.5*10^-6

RESISTANCE=67.5*10^-6/0.785*10^-6

                      = 85.98

                      =86 OHMS.

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Answer 2

Answer:length=2.5Km =2.5×10^-3

radius =0.5mm=5×10^-4

Resistivity p(rho) =2.7×10^-8

Now,R=pL/A

R=pL/pi r^2

=2.7 ×10^-8×2.5×10^3/

3.14×(5×10^-4)^2

=2.7 ×2.5×10^-5/

3.14×25×10^-8

=2.7 ×2.5×10^3/3.14×25

=2.7×25×10^3/3.14×25×10

=2.7×10^3/3.14×10

=2.7×10^2/3.14

27×10^2/3.14×10

=27×10/3.14

=27000/314

=85.98

=86ohm

Explanation: