CBSE BOARD X, asked by skawnwolf, 12 hours ago

Calculate the resistance of 915 meters length of a wire having a uniform cross-sectional area of 0.77 cm^2 if the wire is made of copper having a resistivity of 1.7 × 10^(–6) Ω - cm. *

Answers

Answered by zikku2005
1

Explanation:

In the question, it is given that the resistance of one meter wire is 3 ohms. So the resistance of 1.5 meters of the same wire is given as

1

3×5

=15ohms.

The resistance of a resistor is given by the formula R=ρ

A

L

where ρ is the resistivity of the material the resistor is made of, l is the length of the resistor and A is the cross-sectional area.

Let the resistance of the wire is initially equal to R. R=ρ

A

L

.

When the area of cross-section of the wire is doubled and so the resistance of the wire is given as R

2(A)

L

.

The new resistance is R

=

2

R

.

Hence, the changed resistance of the wire is 15/2=7.5 ohms.

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