Calculate the resistance of a copper wire 1000metre long and 50mm diameter if the resistivity of a copper is 1.7*10-8
Answers
QUESTION :-
Calculate the resistance of a copper wire 1000 metre long and 50 mm diameter if the resistivity of copper is 1.7 × 10 ⁻⁸ Ω m.
SOLUTION :-
GIVEN -
length of the wire ( l ) = 1000 m
resistivity of copper = 1.7 × 10⁻⁸ Ω m
diameter of the wire = 50 mm = 50 × 10 ⁻³ m
radius of the wire (r) = diameter / 2
= 50 × 10⁻³ / 2 m
= 25 × 10 ⁻³ m
Area of cross- section of the wire (A) = π r²
= π ( 25 × 10⁻³ m )²
= 3.14 × 625 × 10 ⁻⁶ m²
= 1962. 5 × 10⁻⁶ m²
Resistance = ρ l/A
where,
ρ = resistivity
l = length
A = Area of cross section
putting the given values in the above formula.....
Resistance = ( 1.7 × 10⁻⁸ Ω m ) × 1000 m/ 1962. 5 × 10⁻⁶ m²
→ Resistance = 17/ 1962.5 Ω
→ Resistance = 0.00866 Ω