Question

calculate the resistance of a copper wire of length 2 metre in India of cross section 10 to the power minus 6 metre square is resistivity of copper 1.7 into 10 to the power minus 8 ohm metre

Answer 1

Answer:

Given,

Length = 2m

Area of cross section = 10^-6 sq. m

Resistivity = 1.7 × 10^-8ohm.m

Now, R = p×l/A

R =( 1.7 × 10^-8) × 2/10^-6

R = 3.4 × 10^-8/ 10^-6

R = 3.4 × 10 ^-8-(-6)

R = 3.4 × 10^-8+6

R = 3.4 × 10^-2

R = 0.034 ohm.

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Answer 2

Answer:

0.034ohm

Explanation:

length =2m

area of cross section =10^-6 sq m

Resitivity = 1.7*10^-8 ohm m

Now, R=p*l/A

R=(1.7*10^-8)*2/10^-6

R=3.4*10^-8/10^-6

R=3.4*10^-8-(-6)

R=3.4*10^-8+6

R=3.4*10^-2

R=0.034ohm

Thus, the resistance of copper wire is 0.034ohm