Question

calculate the resistance of a gadget
which withdraws 60mA current from
battery of
18v?​

Answer 1

Answer:

60ma is 0.06 A

R = V/I

=18/0.06

=300ohm

Answer 2

Explanation:

Given :-

I = 60 mA = 60 ×10^(-3)A

V = 18 V

To find :- R

From ohm's law

V= IR

R = 18/( 60 ×10^-3) = 300 Ohm

God bless you !