Question

Calculate the resistance of a metal wire of length 2m and area of cross section 1.55x10-
6m
2
, if the resistivity of the metal be 2.8x10-8Ωm? ()

Answer 1

hope it helps you....

Answer 2

The resistance of the metal wire is $3.6\times 10^{-2}\ \Omega$.

Explanation:

It is given that,

Length of the metal wire, l = 2 m

Area of cross section of the wire, $A=1.55\times 10^{-6}\ m^2$

Resistivity of the metal, $\rho=2.8\times 10^{-8}\ \Omega-m$

We need to find the resistance of a metal wire. The resistance of wire in terms of length and area is given by the below formula as :

$R=\rho\dfrac{l}{A}$

$R=2.8\times 10^{-8}\times \dfrac{2}{1.55\times 10^{-6}}$

$R=0.036\ \Omega$

$R=3.6\times 10^{-2}\ \Omega$

So, the resistance of the metal wire is $3.6\times 10^{-2}\ \Omega$. Hence, this is the required solution.

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