calculate the resistance of a wire of length 6m with inner and outer diameter of 1mm and 2mm respectively .if the cylindrical wire were to be solid of diameter 2mm, how will the resistance change? (resistivity of material is 0.628)
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Answer:
Correct option is A)
The area of cross section of hollow cylinder=A=π(R
2
−r
2
)
=π(4
2
−1
2
)×10
−6
m
2
The length of the cylinder=1m
Resistivity of material=ρ=2×10
−8
Ωm
Hence resistance=
A
ρl
=
π(4
2
−1
2
)×10
−6
2×10
−8
×1
=2.1×10
−3
Ω
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