Calculate the resistance of an aluminium cable of length 10 km and diameter 2.0 mm if the resistivity of
aluminium is 2.7 x 10-8 ohms m.
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Answer: 85.9 ohm
Explanation:
Here ,
L = 10000m
D = 2mm
r = D/2 = 1 × 10^(-3)m
P = 2.7 × 10^(-8)ohm m
R = ?
we know that ,
R = pL/A
A = πr²
A = 22/7 × 1 × 10^[(-3)]²
R = 2.7 × 10^(-8) × 1000 × 1/[ 22/7 × 1 × 10^[(-3)]² ]
R = 85.9 ohm ≈ 86 ohm
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