Calculate the resistance of an aluminium cable of length 10 km and diameter 20 mm if the resistivity of aluminium is 2.7× 10^(-8) Ωm
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Answered by
3
I think it will be the answer approximately
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yashchouhan24:
r u shure
??
i.e approximately=86ohm I'm sure
k thanx
how did u multiplyy (10*10*10^-6)
Answered by
2
R=pL/A
Where p is resistivity
Putting the values
R= 2.7(10^-8 ) 10 (10^3) /pie r^2
In question diameter is given as we know that r=d/2 so put this value in Above eq
R= 2.7(10^-8) 10(10^3) 4 /pie (20(10-3)^2
By solving without calculator we get
R= 0.8 ohm
Where p is resistivity
Putting the values
R= 2.7(10^-8 ) 10 (10^3) /pie r^2
In question diameter is given as we know that r=d/2 so put this value in Above eq
R= 2.7(10^-8) 10(10^3) 4 /pie (20(10-3)^2
By solving without calculator we get
R= 0.8 ohm
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