Calculate the resistance of an aluminum wire of 60cm and area of cross section 1mm square given that the specific resistance of aluminum is 26 into 10raiseto-2
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Answered by
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The resistance R then,
R=¶×L÷A
where, L is the length=60cm=0.6m
A is the cross section area=1 mm^2=(10^-6) m^2
and ¶ is the specific resistance.
then R=(26×10^-2 )×0.6÷(10^-6)
=156×10^3 ohm
=156 kilo ohm.
R=¶×L÷A
where, L is the length=60cm=0.6m
A is the cross section area=1 mm^2=(10^-6) m^2
and ¶ is the specific resistance.
then R=(26×10^-2 )×0.6÷(10^-6)
=156×10^3 ohm
=156 kilo ohm.
saikat1998:
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Answered by
0
Hi user..,,,,,,
____________________________________________________________
QUESTION:- Calculate the resistance of an aluminum wire of 60cm and area of cross section 1mm square given that the specific resistance of aluminum is 26x10^-2
ANSWER:- GIVEN
=> resistance =pL/A
=> length =60cm =0.6 m
=> p=26x10^-2
=>areas area of cross section 1mm2=(10^-6)m^2
=> R =. 26 x10^-2 x0.6/(10^-6)
=> 156x10^-3ohm
_____________________________________________________________________
____________________________________________________________
QUESTION:- Calculate the resistance of an aluminum wire of 60cm and area of cross section 1mm square given that the specific resistance of aluminum is 26x10^-2
ANSWER:- GIVEN
=> resistance =pL/A
=> length =60cm =0.6 m
=> p=26x10^-2
=>areas area of cross section 1mm2=(10^-6)m^2
=> R =. 26 x10^-2 x0.6/(10^-6)
=> 156x10^-3ohm
_____________________________________________________________________
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