Calculate the resistance of copper wire 50 m long and diameter 1 mm. Given resistivity of copper equals to 1.7x10-8 Ω-m
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Answer:
R=1.08
Explanation:
Given l=50m
d=10^-3m
r=1/2*10^-3
a=πr²
resistivity=1.7*10^-8
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Ans: 1.08 Ω
Given l=50m
d=10^-3m
r=1/2*10^-3
a=πr²
resistivity=1.7*10^-8
solving part
R={( 1.7 * 10^-8) * (50)} / {(22/7) * 10^-6/4)}
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