Calculate the resistance of wire 10m long that has a diameter of 2mm and resistivity of 0.0263
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we know that
r =( rho× l) /a
where r = resistance
rho = resistivity
l = length
and a = area .
given ,
resistivity = 2.63× 10^-2
l = 10m
d = 2mm = 0.002m
then ,area = πr^2
= 1256× 10 ^ -8
r = (2.63× 10^-2 × 2)/1256× 10^-8
= 0.004 × 10^6
( approx )
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Answer:
1.315
Explanation:
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