calculate the resistance of wire when 4 ohm resistance wire is doubled
Answers
Answered by
1
Explanation:
It means its length will get half and area of cross section will get doubled.
Thus, R' = p' l'/A'
= p (l /2) ÷ 2A
= !/4 (p l / A) = 1/4R = 1/4 × 4
= 1Ω.
Answered by
1
Answer:
Resistance = (pl)/a
l = length of wire
a = area of wire
WIRE IS DOUBLED SO LENGTH IS DOUBLED
let assume R is initial resistance
R' = new resistance
R' = (2pl)/a
R' = 2R
R' = 2*4 = 8ohm
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