Question

calculate the resistanse of wire 10 m long taht has a diameter of 2 mm and resistivity of 2.63×10^-2​

Answer 1

we know that

r =( rho× l) /a

where r = resistance

rho = resistivity

l = length

and a = area .

given ,

resistivity = 2.63× 10^-2

l = 10m

d = 2mm = 0.002m

then ,area = πr^2

= 1256× 10 ^ -8

r = (2.63× 10^-2 × 2)/1256× 10^-8

= 0.004 × 10^6

( approx )

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Answer 2

Answer:

7.6×10^-5

Explanation:

lenght = l = 10m

width = w = 2mm = 0.002m

current = I = 2.63×10^-2

Resistence = R = ?

V=IR

R=V/I

V=l×w=10×0.002=0.02m²

R=7.6×10^-5 ohm