Question

calculate the resistivity of the given material whose resistance is 2 ohms , length and area of cross section are 15 cm and 25 CM² respectively.​

Answer 1

given,

resistance of material - 2 ohms

length of material -15 cm

area of cross section-25 cm^2

resistance =

resistivity*length /area of cross section

resistivity = resistance* area of cross section / length

$2 \times 25 \div 15$

$2 \times 5 \div 3$

= 2*1.66

=3.32ohm meter

hope answer may got

Answer 2

The resistivity of the given material is $3.33$ Ω/m

Step by step explanation

Given Data:

The resistance of the material$=2$Ω

The length of the material$=15cm$

$=0.15m$

Area of cross section of the material$=25cm^{2}$

$=0.25m^{2}$

To find:

We must find the resistivity of the given material.

Formula to be used:

ρ$=\frac{rA}{l}$

where:ρ$=$resistivity

$r=$resistance

$l=$length

$A=$area of cross section

Solution:

Using the formula:

ρ$=\frac{rA}{l}$

$=2$×$\frac{0.25}{0.15}$

$=3.33$Ω$/m$

Therefore the resistivity of the given material is $3.33$Ω$/m$

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