Question

calculate the resultant resistance of the given circuit.​

Answer 1

Answer:

Current Electricity

Explanation:

Total resistance of circuit is 18 Ω

Answer 2

→ For upper condition of two resistances ,

As the resistances are attached in parallel manner , So Total Resistance of 1st combination will be

1 / R = 1 / R1 + 1 / R2

• R = Total resistance of upper combination
• R1 = First resistance = 10 Ω
• R2 = Second resistance = 40 Ω

1 / R = 1 / 10 + 1 / 40

• 1 / R = 4 + 1 / 40
• R = 40 / 5
• R = 8

→ For Second condition of three resistances given in lower side in the circuit ,

Resistances are in parallel manner again ,

So , Total Resistance of this combination will be ,

1 / R° = 1 / R1 + 1 / R2 + 1 / R3

• R° = Total resistance of second combination
• R1 = 1st Resistance = 30 Ω
• R2 = 2nd resistance = 20 Ω
• R3 = 3rd resistance = 60 Ω

1 / R° = 1 / 30 + 1 / 20 + 1 / 60

• 1 / R° = 2 + 3 + 1 / 60
• R° = 60 / 6
• R° = 10

Now , to find Total resistance in the circuit we need to calculate the Resistance of 1st combination of two resistances and 2nd combination of Three resistances.

→ As we have the total values of Resistances of 1st and 2nd Combination So ,

Total Resistance "with accordance to the Series connection of upper and lower combination" will be ,

Total Resistance = R + R°

• = ( 8 + 10 ) Ω
• = 18 Ω

So , the total Resistance of the circuit is = 18 Ω