Question

calculate the resultant torque from the following diagram ​

Answer 1

Anticlockwise moment due to A = (20*1) N m = 20 N m

Clockwise moment due to B = (30*4) N m = 120 N m

Anticlockwise moment due to C = (80*3) N m = 240 N m

Moment due to D = (200*0) N m = 0 N m (notice that the the line of action of force D passes through the axis of rotation O, so the perpendicular distance of the line of action of force D from the axis of rotation O is 0 m)

Clockwise moment due to E = (50*5) N m = 250 N m

Therefore, total anticlockwise moment = (20 + 240) N m = 260 N m

and total clockwise moment = (120 + 250) N m = 370 N m

Therefore resultant moment = (370 - 260) N m = 110 N m (clockwise)

(I am not using the negative sign for clockwise moment here, instead I am calculating the total anticlockwise and clockwise moments. Here, since the total clockwise moment on the body is greater, I have subtracted the total anticlockwise moment from the total clockwise moment, and calculated the resultant moment on the body)