calculate the resulting solution obtained by adding 5gram of Naoh to 250ml of M/4 naoh solution (density equal to 1.05 g/cm^3 ) the density of the resulting solution is 1.08g/ml
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Hey Buddy here's ur answer
No. Of Moles of NaOH (which is to be added) = 5/40 (Molar mass of NaOH =40) = 1/8 = 0.125
No. of Moles of NaOH in 250 ml soln (which is to be added) = 1 litre has 1/4 Moles of NaOH . So 1/4 litre of soln will have 1/16 Moles of NaOH.
Moles = 1/16 = 0.0625
After mixing total no. of Moles = 0.0625+0.125 = 0.1875 and volume of solution after mixing is 0.250 litre
So molarity = Moles of solute / volume of solution in litre
Molarity = 0.1875/0.2501 = 0.75 M
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