Physics, asked by vvasu, 18 days ago

Calculate the rise of a liquid of density 103 kg m-3 in a long capillary tube
of radius 0 × 2 · 10-3 m. Given, the surface tension of the liquid for the
material of that capillary is 7 × 27 · 10-2 N/m. (Take g = 9 × 8 m s-2, angle of
contact = 0°

Answers

Answered by singhaarjun002
1

Answer:

Given : 

Radius of capillary tube = 0.1mm

Surface tension of water = 7x10-2 N/m

Angle of contact = 0° • Density of water = 1000kg/m

Acceleration due to gravity = 9.8m/s T

To find:

Height of water column inside the capillary tube.

Formula: 

When a capillary tube of radius 'r' is dipped in a liquid of density p and surface tension T, the liquid rises or falls through a distance, 

H=ρgr2Tcosθ=1000×9.8×0.1×10−32×7×10−2×cosθ=0.142m

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